1) (y-z)(12x^2-6x)+(y-z)(12x^2+6x)
2) a(b-c)+d(b-c)-c(c-b)
3) a(b-3)-(3-b)-b(3-b)
4) 5(a-b)^2+(a+b)(a-b)
5) 2a(x-y)-(y-x)
6) a^2(x-y)-(x-y)
7) 6x^2-3+7x(6x^2-3)+4y(3-6x^2)
Những câu hỏi liên quan
1) (y-z)(12x^2-6x)+(y-z)(12x^2+6x)
2) a(b-c)+d(b-c)-c(c-b)
3) a(b-3)+(3-b)-b(3-b)
4) 5(a-b)^2+(a+b)(a-b)
5) 2a(x-y)-(y-x)
6) a^2(x-y)-(x-y)
7) 6x^2 -3+7x(6x^2-3)+4y(3-6x^2)
a) 12x2y-18xy2-30x2y2
b)10x(2x-y)-15x2(2x-y)
c)27x2(y-1)-9x2(1-y)
d)(a-b)2-(b-a)
e)(a-b)+(b-a)2
f)a(b-c)+c(b-c)-(c-d)
g)6x2-3+7x(6x2-3)+4y(3-6x2)
i)(12x2+6x)(y-z)+(2y+z)(12x2+6x)
k)5(a-b)2-(a+b)(b-a)
1. Phân tích...nhân tử:
a) 2a ( x - y ) - ( y - x )
b) a2 ( x - y ) - ( y - x )
c) x ( x - y ) + y ( y - x ) - 3 ( x - y )
d) 6x2 - 3 + 7x ( 6x2 - 3 ) + 4y ( 3 - 6x2 )
2. Tìm x:
a) x2 + 2x = 0
b) x ( x - 5 ) = 5 - x
c) ( x + 1 ) ( 6x2 + 2x ) + ( x - 1 ) ( 6x2 + 2x ) = 0
2 .tìm x
a , x ( x + 2 ) = 0
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
b, x ( x-5 )= 5 -x
<=> x ( x-5 ) + x - 5 = 0
<=> x (x-5) + ( x-5)= 0
<=> (x-5)(x+1 )=0
\(\Leftrightarrow\left\{{}\begin{matrix}x-5=0\\x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)
c) ( x + 1 ) ( 6x2 + 2x ) + ( x - 1 ) ( 6x2 + 2x ) = 0
\(\Leftrightarrow\) ( 6x2 + 2x ) \([\)(x+1)(x-1)\(]\)=0
\(\Leftrightarrow\) \(\left\{{}\begin{matrix}2x\left(3x+1\right)=0\\x^{2^{ }}-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x=0\\3x+1=0\\x^2-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=\frac{-1}{3}\\x=1\end{matrix}\right.\)
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1 ,a) 2a ( x - y ) - ( y - x ) = 2ax - 2ay - y + x
= x ( 2a + 1 ) - y ( 2a + 1 )
= ( 2a + 1 ) ( x - y )
b) a2 ( x - y ) - ( y - x ) = a2x - a2y - y + x
= x ( a2+ 1 ) - y ( a2 +1 )
= ( a2+1 ) - (x-y )
c) x ( x - y ) + y ( y - x ) - 3 ( x - y ) = x 2 - xy -+ y 2 - xy - 3x + 3y
= x2 - 2xy + y2 -3x + 3y
= (x-y)2 -3 ( x - y )
= ( x-y ) ( x-y+3)
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1/2.(6x-2y).(3x+y)
(2/3z-2/5x).(1/3z+1/5x).1/2
(5y-3x).1/4.(12x+20y)
(3/4y-1/2x).(x+3/2y).2
(a+b+c).(a+b-c)
(x-y+z).(x+y-z)
mng giúp mình vs ạ
\(\dfrac{1}{2}\left(6x-2y\right)\left(3x+y\right)=\dfrac{1}{2}.2\left(3x-y\right)\left(3x+y\right)=9x^2-y^2\)
\(\left(\dfrac{2}{3}z-\dfrac{2}{5}x\right)\left(\dfrac{1}{3}z+\dfrac{1}{5}x\right).\dfrac{1}{2}=\left(\dfrac{1}{3}z-\dfrac{1}{5}x\right)\left(\dfrac{1}{3}z+\dfrac{1}{5}z\right).2.\dfrac{1}{2}=\dfrac{1}{9}z^2-\dfrac{1}{25}x^2\)
\(\left(5y-3x\right).\dfrac{1}{4}\left(12x+20y\right)=\left(5y-3x\right)\left(5y+3x\right).4.\dfrac{1}{4}=25y^2-9x^2\)
\(\left(\dfrac{3}{4}y-\dfrac{1}{2}x\right)\left(x+\dfrac{3}{2}y\right)=\left(\dfrac{3}{2}y-x\right)\left(\dfrac{3}{2}y+x\right)=\dfrac{9}{4}y^2-x^2\)
\(\left(a+b+c\right)\left(a+b+c\right)=\left(a+b+c\right)^2=a^2+b^2+c^2+2ab+2bc+2ac\)
\(\left(x-y+z\right)\left(x+y-z\right)=x^2-\left(y-z\right)^2=x^2-y^2-z^2+2yz\)
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a: \(\dfrac{1}{2}\left(6x-2y\right)\left(3x+y\right)=\left(3x-y\right)\cdot\left(3x+y\right)=9x^2-y^2\)
b: \(\left(\dfrac{2}{3}z-\dfrac{2}{5}x\right)\left(\dfrac{1}{3}z+\dfrac{1}{5}x\right)\cdot\dfrac{1}{2}\)
\(=\left(\dfrac{1}{3}z-\dfrac{1}{5}x\right)\left(\dfrac{1}{3}z+\dfrac{1}{5}x\right)\)
\(=\dfrac{1}{9}z^2-\dfrac{1}{25}x^2\)
c: \(\left(5y-3x\right)\cdot\dfrac{1}{4}\cdot\left(12x+20y\right)\)
\(=\left(5y-3x\right)\left(5y+3x\right)\)
\(=25y^2-9x^2\)
d: \(\left(\dfrac{3}{4}y-\dfrac{1}{2}x\right)\left(\dfrac{3}{2}y+x\right)\cdot2\)
\(=\left(\dfrac{3}{2}y-x\right)\left(\dfrac{3}{2}y+x\right)\)
\(=\dfrac{9}{4}y^2-x^2\)
e: \(\left(a+b+c\right)\left(a+b-c\right)\)
\(=\left(a+b\right)^2-c^2\)
\(=a^2+2ab+b^2-c^2\)
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Phân tích đa thức thành nhân tử a) A = x . y - x^2 - y^2 + 4 . x + 5
b) B = 19 . x^2 + 54 . y^2 + 16 . z^2 - 16 . x . z -24 .y . z +36 . x . y + 5
c) C = x . y . ( x - 2 ) . ( y + 6 ) + 12 . x^2 - 24 . x + 3 . y^2 + 18 . y + 2016
d) 12.x^4 +3.x^3+x^2-2
e) x^4+3x^3-x^2-4x+2
g) x^4+6x^3+7x^2-6x+1
h)x^9-x^7-x^6-x^5+x^4+x^3+x^2+1
tim a,b,c,d thoa man a^2+b^2+c^2+d^2-ab-bc-cd-d+2/5=0
Tính giá trị biểu thức:
1) (a+b+c)^2 + (-a+b+c)^2 + (a-b+c)^2 + ( a+b-c)^2 với a^2+b^2+c^2= 10
2) 3(x^2+y^2)- (x^3+y^3)+1 tại x+y=2
3) 8x^3 -12x^2 y+6x y^2 -y^3+12x^2-12xy+3 y^2+6x-3y+11 với 2x-y=9
Phân tích đa thức thành nhân tử1. (a+b)3+(c-a)3-(b+c)32. xy(x+y)+yz(y+z)+xz(x+z)+2xyz3. (x+y+z)-x3-y3-z34. (x+y)2+3(x+y)+25. 5x2+6xy+y26. a2(b-c)+b2(c-a)+c2(a-b)7. a3+4a2-29a+248. x4+6x3+7x2-6x+19. x3+6x2+11x+610.(x+1)(x+3)(x+5)(x+7)+1511. (x-y)3+(y-z)3+(z-x)3
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Phân tích đa thức thành nhân tử
1. (a+b)3+(c-a)3-(b+c)3
2. xy(x+y)+yz(y+z)+xz(x+z)+2xyz
3. (x+y+z)-x3-y3-z3
4. (x+y)2+3(x+y)+2
5. 5x2+6xy+y2
6. a2(b-c)+b2(c-a)+c2(a-b)
7. a3+4a2-29a+24
8. x4+6x3+7x2-6x+1
9. x3+6x2+11x+6
10.(x+1)(x+3)(x+5)(x+7)+15
11. (x-y)3+(y-z)3+(z-x)3
Phân tích đa thức thành nhân tử1. (a+b)3+(c-a)3-(b+c)32. xy(x+y)+yz(y+z)+xz(x+z)+2xyz3. (x+y+z)-x3-y3-z34. (x+y)2+3(x+y)+25. 5x2+6xy+y26. a2(b-c)+b2(c-a)+c2(a-b)7. a3+4a2-29a+248. x4+6x3+7x2-6x+19. x3+6x2+11x+610.(x+1)(x+3)(x+5)(x+7)+1511. (x-y)3+(y-z)3+(z-x)3
Đọc tiếp
Phân tích đa thức thành nhân tử
1. (a+b)3+(c-a)3-(b+c)3
2. xy(x+y)+yz(y+z)+xz(x+z)+2xyz
3. (x+y+z)-x3-y3-z3
4. (x+y)2+3(x+y)+2
5. 5x2+6xy+y2
6. a2(b-c)+b2(c-a)+c2(a-b)
7. a3+4a2-29a+24
8. x4+6x3+7x2-6x+1
9. x3+6x2+11x+6
10.(x+1)(x+3)(x+5)(x+7)+15
11. (x-y)3+(y-z)3+(z-x)3
6,
=a4 [-(a-b)-(c-a)] + [b4(c-a)+c4(a-b)]
=rồi nhóm hạng tử chung lại
=và sau đó tách ra bằng hằng đẳng thức
kết quả =(a-b)(c-a)(c-b)(a2+b2+c2+ab+bc+ca)
Bài này khá dài nên mk nhác viết , bn cố gắng làm bài nhé !
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a)x^2(x-3)-4x+12 b)2a(x+y)-x+y c)6x^2-12x-7x+14 d)xy-y^2-3x+3y f)x^2y+xy^2-4x-4y g)10ax-5ay-7x+14 j)a^3-a^2+9a-9(tính nhân tử chung)
a: \(x^2\left(x-3\right)-4x+12\)
\(=x^2\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)
b: \(2a\left(x+y\right)+x+y=\left(x+y\right)\left(2a+1\right)\)
c: \(6x^2-12x-7x+14\)
\(=6x\left(x-2\right)-7\left(x-2\right)\)
\(=\left(x-2\right)\left(6x-7\right)\)
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